Answer
No.of electrons=$2.25\times10^{20}$
Work Step by Step
As we know that
i=$\frac{\Delta{q}}{\Delta{t}}$
or
$\Delta{q}$=i$\Delta{t}$
putting the values, we get
$\Delta{q}=0.300A\times120s$
$\Delta{q}=36 C$
We also know that
$\Delta{q}=$No.of electrons .$\frac{1.6\times10^{-19}C}{electron}$
$No.of electrons=$$\frac{\Delta{q}}{1.6\times10^{-19}C/electron}$
putting the values
$No.of electrons=$$\frac{36}{1.6\times10^{-19}C/electron}$
$No.of electrons=$$2.25\times10^{20}$
