Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 21 - Coulomb's Law - Problems - Page 626: 27a

Answer

q=$3.2\times 10^{-19}C$

Work Step by Step

Electrostatic force is given as: $F=\frac{Kq_1q_2}{r^2}$ The ions are identical, so $q_1=q_2=q$ Hence, $F=\frac{Kq^2}{r^2}$ This simplifies to: $q^2=\frac{F.r^2}{K}$ $q=\sqrt{\frac{F}{K}}r$ Plugging in the known values, we obtain: $q=\sqrt\frac{3.7\times10^{-9}}{9\times10^9}.(5.0\times 10^{-10})$ q=$3.2\times 10^{-19}C$
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