Answer
$n=6.3\times10^{11}$
Work Step by Step
We know:
$q=ne$ where 'n' is the number of electrons and 'e' is the charge on an electron
$n=\frac{q}{e}$
Plugging in the known values, we obtain:
$n=\frac{1.0\times10^{-7}}{1.602\times10^{-19}}$
$n=6.3\times10^{11}$
