Answer
$n=2$
Work Step by Step
We know that:
$q=ne$
$n=\frac{q}{e}$
Plugging in the known values, we obtain:
$n=\frac{3.2\times10^{-19}}{1.602\times10^{-19}}$
$n=1.99 \approx 2$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 21 - Coulomb's Law - Problems - Page 626: 27b
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