Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 20 - Entropy and the Second Law of Thermodynamics - Problems - Page 607: 52b

Answer

$W = 963 J $

Work Step by Step

The total work done can be calculated by the following equation $W = nRT_H ln2 - nRT_L$ $W = (1.0 mol)(8.31 J/mol.K)(600K) (ln2) - (1.0 mol)( 8.31 J/mol.K) (300K)$ $W = 3456 J - 2493 J $ $W = 963 J $
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