Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 20 - Entropy and the Second Law of Thermodynamics - Problems - Page 607: 51a

Answer

$\Delta V=87\frac{m}{s}$

Work Step by Step

We know that: $V_p=\sqrt\frac{2RT}{M}$ and $V_{rms}=\sqrt\frac{3RT}{M}$ Now, we use the two above equations to form: $\Delta V=V_{rms}-V_p=(\sqrt3 -\sqrt2)\times \sqrt\frac{RT}{M}$ We plug in the known values to obtain: $\Delta V=(\sqrt3 -\sqrt2)\times \sqrt\frac{8.314(250)}{0.028}=86.6=87\frac{m}{s}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.