Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 20 - Entropy and the Second Law of Thermodynamics - Problems - Page 607: 50a

Answer

$\Delta S = 6.34 J/K $

Work Step by Step

As, $Q=W=nRT ln(\frac{v_{f}}{v_{i}})$ $\Delta S=\frac{Q}{T} = \frac{W}{T} = nRT ln(\frac{v_{f}}{v_{i}})$ $\frac{v_{f}}{v_{i}} = \frac{0.800}{0.200} = 4.00 $ $\Delta S = (0.55)(8.31)ln(4.00) = 6.34 J/K $
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