Answer
$a = 4.01\times 10^7~m$
Work Step by Step
In part (f), we found that $~~E = -2.37\times 10^{11}~J$
We can find the semimajor axis:
$E = -\frac{GMm}{2a} = -2.37\times 10^{11}~J$
$a = \frac{GMm}{(2)(2.37\times 10^{11}~J)}$
$a = \frac{(6.67\times 10^{-11}~N~m^2/kg^2)(9.50\times 10^{25}~kg)(3000~kg)}{(2)(2.37\times 10^{11}~J)}$
$a = 4.01\times 10^7~m$
