Answer
$T = 1.9~hours$
Work Step by Step
We can find the period:
$T = \sqrt{\frac{3\pi}{G~\rho}}$
$T = \sqrt{\frac{3\pi}{(6.67\times 10^{-11}~N~m^2/kg^2)~(3000~kg/m^3)}}$
$T = 6863~s$
$T = 1.9~hours$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 13 - Gravitation - Problems - Page 384: 80b
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