Answer
$v = 1.20\times 10^4~m/s$
Work Step by Step
We can find the original speed:
$K = \frac{1}{2}mv_0^2 = \frac{GMm}{2r}$
$v_0^2 = \frac{GM}{r}$
$v_0 = \sqrt{\frac{GM}{r}}$
$v_0 = \sqrt{\frac{(6.67\times 10^{-11}~N~m^2/kg^2)(9.50\times 10^{25}~kg)}{4.20\times 10^7~m}}$
$v_0 = 1.228\times 10^4~m/s$
We can find the new speed:
$v = 0.98~v_0$
$v = (0.98)(1.228\times 10^4~m/s)$
$v = 1.20\times 10^4~m/s$
