Answer
$K = 2.16\times 10^{11}~J$
Work Step by Step
In part (c) we found that $~~v = 1.20\times 10^4~m/s$
We can find the kinetic energy:
$K = \frac{1}{2}mv^2$
$K = \frac{1}{2}(3000~kg)(1.20\times 10^4~m/s)^2$
$K = 2.16\times 10^{11}~J$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 13 - Gravitation - Problems - Page 384: 83d
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