Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 12 - Equilibrium and Elasticity - Problems - Page 349: 45a

Answer

The fraction of the brick's mass supported by cylinder A is $~~0.80$

Work Step by Step

It is given that the cylinders originally had the same length. Since the bricks is horizontal, the cylinders must have the same length when they are supporting the brick. Thus $~~strain = \frac{\Delta L}{L}~~$ is equal for both cylinders. We can find the relationship between the forces on each cylinder: $\frac{\Delta L}{L} = \frac{F_A}{A_A~E_B} = \frac{F_B}{A_B~E_B}$ $F_A = \frac{A_A~E_A}{A_B~E_B}~F_B$ $F_A = \frac{(2~A_B)~(2~E_B)}{A_B~E_B}~F_B$ $F_A = 4~F_B$ Therefore, the fraction of the brick's mass supported by cylinder A is $~~0.80$
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