Answer
$6.5\times10^{6}\,N/m^{2}$
Work Step by Step
Given: m=1200 kg and d=2r=$4.8\times10^{-2}\,m$
Shear stress=$\frac{Force}{Area}=\frac{mg}{\pi r^{2}}$
$=\frac{1200\,kg\times9.8\,m/s^{2}}{\pi(2.4\times10^{-2}\,m)^{2}}=6.5\times10^{6}\,N/m^{2}$
