Answer
$1.1\times10^{-5}\,m$
Work Step by Step
Given/Known: We found in the previous section that shear stress=$6.5\times10^{6}\,N/m^{2}$. Also, shear modulus G= $3.0\times10^{10}\,N/m^{2}$ and $L=5.3\,cm$
We want to find the vertical deflection $\Delta x$
Recall:
Shear stress=shear modulus$\times$shear strain
Or shear stress=shear modulus$\times\frac{\Delta x}{L}$
Result: $\Delta x=\frac{shear\,stress\times L}{shear\,modulus}=\frac{6.5\times10^{6}\,N/m^{2}\times5.3\times10^{-2}\,m}{3.0\times10^{10}\,N/m^{2}}$
$=1.1\times10^{-5}\,m$
