Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 12 - Equilibrium and Elasticity - Problems - Page 349: 44a

Answer

$E = 7.5\times 10^{10}~N/m^2$

Work Step by Step

We can find a general equation for Young's modulus: $stress = E \times strain$ $E = \frac{stress}{strain}$ Thus, Young's modulus is the slope of the stress versus strain graph: $E = \frac{150\times 10^6~N/m^2}{0.002}$ $E = 7.5\times 10^{10}~N/m^2$
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