Answer
The vertical component of the force on the strut from the hinge is $~~5960~N$
Work Step by Step
To find $F_y$, the vertical component of the force on the strut from the hinge, we can consider the vertical forces on the strut.
In part (a), we found that $T = 6630~N$
We can find $F_y$:
$F_{net,y} = 0$
$F_y - T~sin~\phi-(45.0~kg)(9.8~m/s^2)-(225~kg)(9.8~m/s^2) = 0$
$F_y = T~sin~\phi+(45.0~kg)(9.8~m/s^2)+(225~kg)(9.8~m/s^2)$
$F_y = (6630~N)~sin~30.0^{\circ}+(45.0~kg)(9.8~m/s^2)+(225~kg)(9.8~m/s^2)$
$F_y = 5960~N$
The vertical component of the force on the strut from the hinge is $~~5960~N$.
