Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 12 - Equilibrium and Elasticity - Problems - Page 346: 13d

Answer

The direction of the force at point B from the lower leg bones is downward.

Work Step by Step

In parts (a) and (b), we found that there is an upward force of $2700~N$ exerted at point A from the muscle. Also note that the floor pushes up at point P with a force of $900~N$ Let "up" be the positive direction. To find the force at point B from the lower leg bones, we can consider the vertical forces exerted on the foot. We can find $F_B$, the force at point B from the lower leg bones: $F_{net,y} = 0$ $2700~N-900~N+F_B = 0$ $F_B = 900~N-2700~N$ $F_B = -1800~N$ Since the force at point B from the lower leg bones is negative, the direction of the force at point B from the lower leg bones is downward.
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