Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 6 - Exercises and Problems - Page 107: 86


a) $ 90\ J$ b) $360 \ J$

Work Step by Step

a) We know that work is equal to the integral of force with respect to distance, and we know that any perpendicular component of a vector will not contribute to work. Thus: $ W =\int_0^3cxydx + \int_0^6 d dy$ $ W =\int_0^3cx(0_dx + \int_0^6 d dy$ $W=6 \times 15 = 90\ J$ b) We use a similar process to find: $ W =\int_0^3cxydx + \int_0^6 d dy$ $ W =\int_0^36cxdx + 90=360 \ J$
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