Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 6 - Exercises and Problems - Page 107: 75


Please see the work below.

Work Step by Step

We know that $W=\int{P}{dt}$ $W=\int ct^2dt$ $W=(\frac{c}{3})t^3$ $W=(\frac{18}{3})t^3$ $W=6t^3$ We plug in the known values to obtain: $W=6(20)^3-6(10)^3$ $W=42000J$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.