Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 6 - Exercises and Problems: 73

Answer

Please see the work below.

Work Step by Step

We know that (a) $P=\frac{energy}{time}$ $\implies P=\frac{\mu m g d}{t}=(\mu mg)(\frac{d}{t})$ We plug in the known values to obtain: $P=(0.78)(95)(9.8)(0.62)=450W$ (b) Now we can find the work as $W=\mu m gd$ We plug in the known values to obtain: $W=(0.78)(95)(9.8)(11)=8000J$
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