## Essential University Physics: Volume 1 (3rd Edition)

We know that (a) $P=\frac{energy}{time}$ $\implies P=\frac{\mu m g d}{t}=(\mu mg)(\frac{d}{t})$ We plug in the known values to obtain: $P=(0.78)(95)(9.8)(0.62)=450W$ (b) Now we can find the work as $W=\mu m gd$ We plug in the known values to obtain: $W=(0.78)(95)(9.8)(11)=8000J$