Answer
Please see the work below.
Work Step by Step
We know that
(a) $P=\frac{energy}{time}$
$\implies P=\frac{\mu m g d}{t}=(\mu mg)(\frac{d}{t})$
We plug in the known values to obtain:
$P=(0.78)(95)(9.8)(0.62)=450W$
(b) Now we can find the work as
$W=\mu m gd$
We plug in the known values to obtain:
$W=(0.78)(95)(9.8)(11)=8000J$
