Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 6 - Exercises and Problems - Page 107: 69


Please see the work below.

Work Step by Step

We know that $P=\frac{mgh}{t}$ $\implies P=\frac{mgdsin(\theta)}{t}$ $P=mgsin(\theta)(\frac{d}{t})$ $P=mgsin(\theta)(v)$ This can be rearranged as: $v=\frac{P}{mgsin(\theta)}$ We plug in the known values to obtain: $v=\frac{35000}{(1750)(9.8)sin(4.5)}$ $v=26\frac{m}{s}$
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