Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 4 - Exercises and Problems - Page 68: 58

Answer

a) $F=42,183 \ N$ b) $F=28,423 \ N$ c) $F=55,943 \ N$ d) $F=42,183 \ N$ e) $F=28,423 \ N$

Work Step by Step

We use Newton's Second Law to find: a) $F=mg=(4300)(9.81)=42,183 \ N$ b) $F=m(a+g)=(4300)(-3.2+9.81)=28,423 \ N$ c) $F=m(a+g)=(4300)(3.2+9.81)=55,943 \ N$ d) $F=mg=(4300)(9.81)=42,183 \ N$ e) $F=m(a+g)=(4300)(-3.2+9.81)=28,423 \ N$
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