## Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson

# Chapter 4 - Exercises and Problems - Page 68: 45

#### Answer

Please see the work below.

#### Work Step by Step

We know that the acceleration of the elevator is equal to g: As $a=\frac{v}{t}$ This can be rearranged as $t=\frac{v}{a}$ $t=\frac{v}{g}$ because $a=g$ $t=\frac{5.2}{9.8}=0.53s$

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