Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 4 - Exercises and Problems - Page 68: 40


$|\vec{F}|=5.77 \ N$ $\theta = 72.17^{\circ}$

Work Step by Step

We use Newton's Second Law to find: $F = ma$ $F=\frac {m\Delta v}{\Delta t}$ $F=\frac {(1.25)(26.8cos(34)\hat{i}+26.8sin(34)\hat{j}-17.4\hat{i})}{3.41}$ $F=1.77\hat{i}+5.49\hat{j}$ Thus, we find: $|\vec{F}|=\sqrt{1.77^2+5.49^2}=5.77 \ N$ $\theta = tan^{-1}(\frac{5.49}{1.77})=72.17^{\circ}$
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