Answer
$|\vec{F}|=5.77 \ N$
$\theta = 72.17^{\circ}$
Work Step by Step
We use Newton's Second Law to find:
$F = ma$
$F=\frac {m\Delta v}{\Delta t}$
$F=\frac {(1.25)(26.8cos(34)\hat{i}+26.8sin(34)\hat{j}-17.4\hat{i})}{3.41}$
$F=1.77\hat{i}+5.49\hat{j}$
Thus, we find:
$|\vec{F}|=\sqrt{1.77^2+5.49^2}=5.77 \ N$
$\theta = tan^{-1}(\frac{5.49}{1.77})=72.17^{\circ}$
