#### Answer

Please see the work below.

#### Work Step by Step

We know that the tension at one end is given as
$T_1=(m+M)a$
We plug in the known values to obtain:
$T_1=(11+1.8)(2.3)=29N$
The tension at the other end is given as
$T_2=Ma$
We plug in the known values to obtain:
$T_2=(11)(23)=25N$
The tension forces are not equal as the handle is not mass-less.