Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 3 - Exercises and Problems: 82

Answer

This means that the slope needs to be 30 degrees below the horizontal.

Work Step by Step

We first find the change in time: $55=28cos(9.5)t \\ t = 1.99 \ s$ We now find the change in y: $\Delta y = -28sin(9.5)(1.99)-\frac{1}{2}g(1.99)^2=-28.65 \ m$ Thus, we find the angle they will be at: $\theta=tan^{-1}(\frac{28.65}{55})=27^{\circ}$ This means that the slope needs to be 30 degrees below the horizontal.
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