Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 3 - Exercises and Problems: 75

Answer

Please see the work below.

Work Step by Step

We know that $5g=\frac{v^2}{R}$ This can be rearranged as: $R=\frac{v^2}{5g}$ We plug in the known values to obtain: $R=\frac{(\frac{1200}{3.6})^2}{5(9.8)}$ $R=2300m$
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