Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 3 - Exercises and Problems - Page 49: 69

Answer

70.416 kilometers per hour

Work Step by Step

In a problem earlier in the chapter, we actually solved for an equation that modeled this exact problem. The equation is: $v_0=\sqrt{xg}=\sqrt{(39)(9.81)}=19.5599\ m/s \times 3.6 = \fbox{70.416 kilometers per hour}$
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