Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 3 - Exercises and Problems: 78

Answer

Please see the work below.

Work Step by Step

We know that the range is given as $R=\frac{(v_{\circ})^2}{g}$ This simplifies to: $v_{\circ}=\sqrt{Rg}$ The maximum altitude is given as $y=\frac{(v_{\circ})^2}{2g}=\frac{Rg}{2g}$ $y=\frac{R}{2}$ We plug in the known values to obtain: $y=\frac{180Km}{2}=90Km$
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