Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 19 - Exercises and Problems - Page 349: 31


The answer is below.

Work Step by Step

We first find the value of Q: $Q_h = \frac{2\times 10^{11}}{.33}=6.06\times10^{11}$ Thus, it follows: $Q_c= 6.06\times10^{11}-2\times10^{11}=4.06\times10^{11}$ We now find: $ m = \frac{4.06\times10^{11}}{4184\times5}= 1.94 \times 10^7$ Thus, the answer is: $= 1.94\times10^7-1.8\times10^7=1.4\times10^6$
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