Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 19 - Exercises and Problems - Page 349: 25


1/64, 5/16

Work Step by Step

We see that there are $2^6=64$ possible options. a) Only one of these options will result in all molecules being on one side of the box. Thus, the answer is 1/64. b) We find that the number of possible ways this could happen is: $ \frac{6!}{3!3!}$ This gives: 20 So, our answer is: $20/64=5/16$
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