Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 19 - Exercises and Problems: 21

Answer

Please see the work below.

Work Step by Step

We know that $\Delta S=\frac{Q}{T}$ We plug in the known values to obtain: $\Delta S=\frac{(650)(4184)}{273+37}$ $\Delta S=8800\frac{J}{K}$
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