Answer
Please see the work below.
Work Step by Step
We know that
$\Delta S=\frac{Q}{T}$
We plug in the known values to obtain:
$\Delta S=\frac{(650)(4184)}{273+37}$
$\Delta S=8800\frac{J}{K}$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 19 - Exercises and Problems - Page 349: 21
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