## Essential University Physics: Volume 1 (3rd Edition)

We know that the heat absorbed from the water is $Q_c=mL_f$ We plug in the known values to obtain: $Q_c=(0.670)(334000)$ $Q_c=223780J$ For a refrigerator $COP=\frac{Q_c}{W}$ This can be rearranged as: $W=\frac{Q_c}{COP}$ We plug in the known values to obtain: $W=\frac{223780}{4.2}$ $W=53000J$