Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 18 - Exercises and Problems: 61

Answer

334 K

Work Step by Step

We find: $\frac{T_1^{\gamma}}{p_1^{\gamma-1}}=\frac{T_2^{\gamma}}{p_2^{\gamma-1}}$ Simplifying this equation, it follows: $T_2=\sqrt[1.3] {\frac{T_1^{\gamma}(p_2^{\gamma-1})}{p_1^{\gamma-1}}}$ $T_2=\sqrt[1.3] {\frac{273^{1.3}(240^{.3})}{100^{.3}}}=334K$
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