Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 18 - Exercises and Problems: 60

Answer

Please see the work below.

Work Step by Step

We know that for an adiabatic process $T_2V_2^{\gamma-1}=T_3V_3^{\gamma-1}$ We plug in the known values to obtain: $(273)(\frac{1}{3})^{\frac{7}{5}-1}=T_3(\frac{1}{5})^{\frac{7}{5}-1}$ $T_3=335K$
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