Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 18 - Exercises and Problems - Page 332: 58


$.026 \ J$

Work Step by Step

We will call the process of inflating the lung isothermal, for the temperature is constant. Thus, the work done is equal to the area under the curve, which we approximate to be: $W = (.5)(1.5\ L)(.035 \ Pa)=.026 \ J$
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