## Essential University Physics: Volume 1 (3rd Edition)

We know that: $\frac{T_2}{T_1} = { (\frac {V_1}{V_2})}^{ \gamma -1}$ We know that the volume is cut by a factor of 4 and that $\gamma$ is equal to 1.4. This gives: $T_2= (\frac {4}{1})^{.4} \times 291 K$ We know: $\Delta T = T_2-T_1=216 K$