Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 18 - Exercises and Problems - Page 330: 16


a) 2.7 kJ b) 6.3 kJ

Work Step by Step

a) We must first figure out how much energy is gained by the water: $ W = mc \Delta t \\ W = (.5kg)*(4.18)(3) = 6.3 kJ$ Because the system gains 6.3 kJ, but 9kJ of work is done, it follows that the surroundings must have gained $ 9 - 6.3 = 2.7$ kJ of energy. b) If no energy had been lost, only the energy to increase the temperature would have been needed. This value is: $6.3$ kJ.
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