Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 18 - Exercises and Problems: 18

Answer

Please see the work below.

Work Step by Step

We know that $\frac{dU}{dt}=\frac{dQ}{dt}+\frac{dW}{dt}$ This can be rearranged as: $\frac{dQ}{dt}=\frac{dU}{dt}-\frac{dW}{dt}$ We plug in the known values to obtain: $\frac{dQ}{dt}=45-165$ $\frac{dQ}{dt}=-120W$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.