## Essential University Physics: Volume 1 (3rd Edition)

$W = 2p_1V_1$
We know that: $W = \int p dV$ The area under the curve going from A to C is 0, so the gas does no work. We then find the work involved in going from C to B, which is given by the rectangular area under the curve. $W = (2p_1-0)*(2V_1-V_1)$ $W = 2p_1V_1$