Answer
Please see the work below.
Work Step by Step
(a) We can find the heat capacity as
$heat\space capacity =\frac{2520}{15}$
$heat\space capacity =168\frac{J}{K}$
(b) We know that
$Q=mc\Delta T$
This can be rearranged as:
$c=\frac{Q}{m\Delta T}$
We plug in the known values to obtain:
$c=\frac{2520}{(0.350)(15)}$
$c=480\frac{J}{Kg\space C}$
