Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 16 - Section 16.4 - Exercises and Problems: 25

Answer

Please see the work below.

Work Step by Step

We know that $E=(2000Kcal)(\frac{4184J}{1 Kcal})=8368000J$ Now we can find the power as $P=\frac{E}{t}$ We plug in the known values to obtain: $P=\frac{8368000}{24\times 60\times 60}$ $P=97W$
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