Answer
Please see the work below.
Work Step by Step
We know that
$E=(2000Kcal)(\frac{4184J}{1 Kcal})=8368000J$
Now we can find the power as
$P=\frac{E}{t}$
We plug in the known values to obtain:
$P=\frac{8368000}{24\times 60\times 60}$
$P=97W$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 16 - Section 16.4 - Exercises and Problems - Page 299: 25
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