Answer
Please see the work below.
Work Step by Step
We know that
$T_F=(\frac{9}{5})T_C+32$
We plug in the known values to obtain:
$68=(\frac{9}{5})T_C+32$
$T_C=20C^{\circ}$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 16 - Section 16.4 - Exercises and Problems - Page 299: 17
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