Answer
Please see the work below.
Work Step by Step
We know that
$T_{1F}=\frac{9}{5}T_c$
We plug in the known values to obtain:
$T_{1F}=\frac{9}{5}(1.4)=2.52^{\circ}F$
$T_{2F}=\frac{9}{5}(3.1)=5.58^{\circ}F$
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.