Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 16 - Section 16.4 - Exercises and Problems: 15

Answer

Please see the work below.

Work Step by Step

We know that $T_{1F}=\frac{9}{5}T_c$ We plug in the known values to obtain: $T_{1F}=\frac{9}{5}(1.4)=2.52^{\circ}F$ $T_{2F}=\frac{9}{5}(3.1)=5.58^{\circ}F$
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