College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 6 - Linear Momentum and Collisions - Learning Path Questions and Exercises - Exercises - Page 216: 31

Answer

$3.7\times10^{2}\,N$

Work Step by Step

Impulse=$F\Delta t=\Delta p$ $\implies F=\frac{\Delta p}{\Delta t}=\frac{m(v_{f}-v_{i})}{\Delta t}=\frac{0.14\,kg(60\,m/s-(-45\,m/s))}{0.040\,s}=3.7\times10^{2}\,N$
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