Answer
15 m/s.
Work Step by Step
Impulse= Change in momentum=$mv_{f}-mv_{i}$
Initial horizontal speed $v_{i}=0$
Therefore, Impulse= $mv_{f}-m\times0=mv_{f}$
Or $v_{f}= \frac{I}{m}=\frac{3.0\,Ns}{0.20\,kg}=15\,m/s$
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 6 - Linear Momentum and Collisions - Learning Path Questions and Exercises - Exercises - Page 216: 19
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