#### Answer

6000 N

#### Work Step by Step

Impulse= $F\Delta t= \Delta p$
$\implies F=\frac{\Delta p}{\Delta t}=\frac{0-3.0\times10^{4}kg\,m/s}{5.0\,s}=-6000\,N$
The magnitude of average braking force is 6000 N.

Published by
Pearson

ISBN 10:
0-32160-183-1

ISBN 13:
978-0-32160-183-4

6000 N

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