Answer
6000 N
Work Step by Step
Impulse= $F\Delta t= \Delta p$
$\implies F=\frac{\Delta p}{\Delta t}=\frac{0-3.0\times10^{4}kg\,m/s}{5.0\,s}=-6000\,N$
The magnitude of average braking force is 6000 N.
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 6 - Linear Momentum and Collisions - Learning Path Questions and Exercises - Exercises - Page 216: 20
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