## College Physics (7th Edition)

Impulse I=$\Delta p=mv_{f}-mv_{i}=mv_{f}-m\times0$ ($v_{i}=0$ as the ball is stationary initially) $I= mv_{f}$ or $v_{f}=\frac{I}{m}=\frac{3.2\,Ns}{0.25\,kg}=13\,m/s$