College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 4 - Force and Motion - Learning Path Questions and Exercises - Exercises - Page 137: 48

Answer

a). $269.5N$ b). $381.1N$

Work Step by Step

a). $2T-mg=0$ $T=\frac{mg}{2}=\frac{55\times9.8}{2}=269.5N$ b). $Tcos\theta=\frac{1}{2}mg$ $T=\frac{mg}{2cos\theta}=\frac{55\times9.8}{2cos45^{\circ}}=381.1N$
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