College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 4 - Force and Motion - Learning Path Questions and Exercises - Exercises - Page 137: 44

Answer

a). (2) two forces, b). $5.9m/s^{2}$, c). $20.9m/s$

Work Step by Step

a). Two forces act on the skier - the weight , mg and the normal force N. b). $w_{x}=mgsin\theta$ $a=\frac{mgsin\theta}{m}=gsin\theta=9.8sin37^{\circ}=5.9m/s^{2}$ c). $v^{2}=u^{2}+2aS=5^{2}+2\times 5.9\times 35$ $v=20.9m/s$
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